tgseaver

Is there a price that you just can't walk away from? I want a 2015 Lariat,build price is $51,000...... now I see a 2014 Lariat for $48,000 sticker and I say to my self if I can get that truck for $35,000 I would have to buy it.The best I think I can do on the 2015 is $47,000. So to save $12,000,I would have to pull the trigger.

NProbst37

I'm in that same boat. My number is 9k off, i think. I really like the 2015s, test drove one for the second time yesterday. Just cant justify 5k more for a similarly equipped 15 though. It would have to be closer to 3-4k price difference for me. The 2015 3.5 ecoboost felt faster than my tuned 2011 which had me surprised!

Going to try my hand at a 14 fx4 tomorrow. Going to start negotiations at 13k off. When i test drove it the thing barely started the battery was so dead... so i know it's not getting any attention .

I guess if they wont go more than 8k off I'll just order a 2015.

Shelbygt500

Even if it was free I would still buy my 15. I have had 3 of this generation trucks and its time for something totally new.

pb65stang

Probably in excess of $15k. Having now sat in both trucks, the 14 just doesn't compare to the 15, and I would kick myself unless I got a good enough price that I could trade it in in 2-3 years and still make out OK on a 2017-18.

BlueOval5.0

I've thought about this too. Not sure what to do. Wife and I going to look next week. I really like the '15 style and all but if the price difference is where it needs to be, I could lean towards the '14.

1fifty

If only looking at the money side of this, $7500 minimum difference because it is already 2015.

VivasFX4

Just picked up a 2014 FX4. Stickered at 52k, ended up paying 37k, yeah I felt good about it.

ducgsxr

I'm getting nearly $9K off my 2015 between D plan, incintives, and not paying a few fees. For a 2014, considering where it will be on a depreciation curve in 5 years... It would have to be $20K off sticker for me to consider it.

pinocchio

Wouldn't even consider 2014

OldFlick

What he said.