Modifying 2wd front rotor/bearing to separate components
#22
Senior Member
You can get close using math. Torque formula, a piece of pipe and your body weight. Torque = force x distance
Desired torque is 295 ft. lbs. my weight is 170 lbs.
295/170=1.73 x 12 inches = 20.76 inches. Put the piece of pipe on your socket wrench and tighten the nut until the pipe will support you body weight standing at 20.76" from the nut. Nut should be torqued to 295ish ft lbs.
Google picture from the web (not an F150). This guy weighs more than me or has a lower axle torque value since he has 15" marked on the pipe and he should have his weight centered over the mark.
Desired torque is 295 ft. lbs. my weight is 170 lbs.
295/170=1.73 x 12 inches = 20.76 inches. Put the piece of pipe on your socket wrench and tighten the nut until the pipe will support you body weight standing at 20.76" from the nut. Nut should be torqued to 295ish ft lbs.
Google picture from the web (not an F150). This guy weighs more than me or has a lower axle torque value since he has 15" marked on the pipe and he should have his weight centered over the mark.
Torque 101.
#23
Senior Member
Thread Starter
I did the math...I wouldn't have enough length to put both my feet on the bar. I carry a bit more weight than I would like, but I am going to figure out a way.
Looking up rotor pros, thanks for the suggestions!
Now tell me where I can get the correct replacement cotter pins?
Looking up rotor pros, thanks for the suggestions!
Now tell me where I can get the correct replacement cotter pins?
#24
Senior Member
I did the math...I wouldn't have enough length to put both my feet on the bar. I carry a bit more weight than I would like, but I am going to figure out a way. Looking up rotor pros, thanks for the suggestions! Now tell me where I can get the correct replacement cotter pins?